What is Circular Queue Data Structure ?
What is Circular Queue Data Structure - Everything You Need to Know.
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Imagine a highway toll booth system. Cars arrive continuously and form a queue. Each car is served and moves through. After serving a car, the booth does not shut down and refuse new cars just because some positions at the start of the lane are now empty. It keeps accepting new cars from behind while serving from the front.
Now imagine if the toll booth worked like a naive linear queue implemented with an array. Every time a car is served and leaves the front, that position in the lane becomes permanently unusable. After serving 100 cars, 100 positions at the front of the lane are wasted. The system would refuse new cars and report “lane full” even though 100 empty slots exist right there at the beginning of the lane.
This is exactly the problem with the linear array-based queue, and it is exactly why the circular queue was invented.
A circular queue (also called a ring buffer) is a linear data structure that follows the FIFO (First In, First Out) principle, where the last position of the array is connected back to the first position, forming a logical circle. Unlike a linear queue, a circular queue reuses the spaces freed by dequeue operations at the front, eliminating memory waste.
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Break that definition apart:
FIFO principle: The element inserted first is the first one to be removed, just like a regular queue
Last position connected to first: When the rear pointer reaches the end of the array, it wraps back to index 0
Logical circle: The physical array is linear, but the pointer movement treats it as circular using modulo arithmetic
Reuses freed spaces: Once front elements are dequeued, those positions become available for new insertions
A circular queue with SIZE = 5, after several enqueue and dequeue operations:
Physical array: [ -- ] [ 30 ] [ 40 ] [ 50 ] [ -- ]
Index: 0 1 2 3 4
^ ^
FRONT=1 REAR=3
(positions 0 and 4 are free, previously dequeued)
Next enqueue goes to: (3+1) % 5 = 4 → position 4
After that: (4+1) % 5 = 0 → position 0 (WRAP AROUND!)
The array is physically linear but logically circular:
Index 0 → Index 1 → Index 2 → Index 3 → Index 4
^ |
|__________________________________________| (wrap)A circular queue maintains two index pointers:
FRONT: Index of the element that will be removed next (the oldest element)
REAR: Index of the most recently added element
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The entire circular behaviour is driven by one formula applied to both pointers:
Next REAR position: REAR = (REAR + 1) % SIZE
Next FRONT position: FRONT = (FRONT + 1) % SIZEWhen REAR equals SIZE - 1 (the last index) and we increment it: (SIZE - 1 + 1) % SIZE = SIZE % SIZE = 0 The pointer wraps back to index 0, making the physically linear array behave as a circle.
SIZE = 5
# Normal increment:
REAR = 2
REAR = (2 + 1) % 5 = 3 # Normal step forward
# Wrap-around increment:
REAR = 4
REAR = (4 + 1) % 5 = 0 # Wraps back to beginning!Detecting when a circular queue is full requires special care. There are two possible full conditions:
Case 1: FRONT is at index 0 and REAR is at the last index (SIZE - 1).
[ 10 ] [ 20 ] [ 30 ] [ 40 ] [ 50 ]
0 1 2 3 4
FRONT = 0, REAR = 4
FULL: (FRONT == 0 && REAR == SIZE - 1)Case 2: REAR + 1 equals FRONT (REAR has wrapped around and caught up to FRONT).
[ 50 ] [ 10 ] [ 20 ] [ 30 ] [ 40 ]
0 1 2 3 4
FRONT = 1, REAR = 0
FULL: (REAR + 1) % SIZE == FRONT → (0 + 1) % 5 = 1 == FRONT (1)Both cases captured by one combined formula:
isFull: (FRONT == 0 && REAR == SIZE - 1) OR (REAR + 1 == FRONT)
Or using size counter (simpler): isFull: size == capacityThe Classic Bug: Using only
REAR == SIZE - 1as the full condition only catches Case 1. This causes the queue to report full even when there is free space after wrap-around. Always use the full modulo-based check or a separatesizecounter.
# Linear Queue with SIZE = 5
# After enqueuing 5 elements and then dequeuing 3:
# State:
# [ -- ] [ -- ] [ -- ] [ 40 ] [ 50 ]
# 0 1 2 3 4
# FRONT = 3, REAR = 4
# Positions 0, 1, 2 are FREE but UNUSABLE
# Try to enqueue 60:
# rear = rear + 1 = 5
# 5 >= SIZE (5) → Queue reports FULL!
# Even though 3 out of 5 positions are empty!Visual comparison:
Linear Queue after 3 dequeues:
[ -- ] [ -- ] [ -- ] [ 40 ] [ 50 ]
FREE FREE FREE USED USED
Reports "FULL" even though only 2 of 5 slots are occupied!
Circular Queue same state:
[ 60 ] [ -- ] [ -- ] [ 40 ] [ 50 ] ← 60 wraps to position 0
USED FREE FREE USED USED
Only 3 of 5 slots occupied. 60 inserted successfully.This is why circular queues exist. The circular wrap eliminates the logical overflow that arises when the rear pointer reaches the end of a linear array even though dequeued positions at the front are available.
Term | Definition |
|---|---|
FRONT | Index of the oldest element (next to be dequeued). Initially -1 |
REAR | Index of the most recently enqueued element. Initially -1 |
SIZE / CAPACITY | Fixed maximum number of elements the circular queue can hold |
Wrap-around | When REAR reaches SIZE-1 and the next increment sends it to 0 |
Ring buffer | Another name for circular queue: the array acts as a ring |
Overflow | Attempting to enqueue into a full circular queue |
Underflow | Attempting to dequeue from an empty circular queue |
Modulo formula |
|
Full condition |
|
Empty condition |
|
Every circular queue supports six core operations. All primary operations are O(1).
Operation | Description | Time Complexity |
|---|---|---|
| Add element x at the rear. Wrap if needed | O(1) |
| Remove and return the front element. Wrap if needed | O(1) |
| Return front element without removing | O(1) |
| Return rear element without removing | O(1) |
| Return true if queue has no elements | O(1) |
| Return true if queue is at maximum capacity | O(1) |
The enqueue operation adds a new element at the rear of the circular queue.
enqueue(element):
1. Check if queue is full → print "Overflow" and stop
2. If queue is empty (FRONT == -1): set FRONT = 0, REAR = 0
3. Else: REAR = (REAR + 1) % SIZE ← circular increment
4. Place element at queue[REAR]
5. Increment size counter
Queue: [10, 20, 30, --, --], FRONT=0, REAR=2, SIZE=5
enqueue(40):
REAR = (2 + 1) % 5 = 3
queue[3] = 40
Result: [10, 20, 30, 40, --], FRONT=0, REAR=3
enqueue(50):
REAR = (3 + 1) % 5 = 4
queue[4] = 50
Result: [10, 20, 30, 40, 50], FRONT=0, REAR=4
After dequeue() removes 10 and 20: FRONT=2, REAR=4
enqueue(60): ← WRAP-AROUND case!
REAR = (4 + 1) % 5 = 0 ← wraps from 4 to 0
queue[0] = 60
Result: [60, --, 30, 40, 50], FRONT=2, REAR=0class CircularQueue:
def __init__(self, capacity):
self.queue = [None] * capacity
self.capacity = capacity
self.front = -1
self.rear = -1
self.size = 0
def is_empty(self): return self.front == -1
def is_full(self): return self.size == self.capacity
def enqueue(self, element):
if self.is_full():
print("Queue Overflow: circular queue is full")
return False
if self.is_empty():
self.front = 0
self.rear = 0
else:
self.rear = (self.rear + 1) % self.capacity # Circular increment
self.queue[self.rear] = element
self.size += 1
print(f"Enqueued:{element}")
return True
cq = CircularQueue(5)
cq.enqueue(10) # Enqueued: 10
cq.enqueue(20) # Enqueued: 20
cq.enqueue(30) # Enqueued: 30The dequeue operation removes the element at the front of the circular queue and advances the FRONT pointer.
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dequeue():
1. Check if queue is empty (FRONT == -1) → print "Underflow" and stop
2. Store value at queue[FRONT]
3. If only one element left (FRONT == REAR):
set FRONT = -1, REAR = -1 (queue becomes empty)
4. Else:
FRONT = (FRONT + 1) % SIZE ← circular increment
5. Decrement size
6. Return stored valueQueue: [10, 20, 30, 40, 50], FRONT=0, REAR=4, size=5
dequeue():
value = queue[0] = 10
FRONT (0) != REAR (4): more elements remain
FRONT = (0 + 1) % 5 = 1
Returns: 10
dequeue() again:
value = queue[1] = 20
FRONT = (1 + 1) % 5 = 2
Returns: 20
Queue state: [--, --, 30, 40, 50], FRONT=2, REAR=4def dequeue(self):
if self.is_empty():
print("Queue Underflow: circular queue is empty")
return None
value = self.queue[self.front]
if self.front == self.rear: # Only one element left
self.front = -1
self.rear = -1
else:
self.front = (self.front + 1) % self.capacity # Circular increment
self.size -= 1
return value
cq = CircularQueue(5)
for val in [10, 20, 30, 40, 50]:
cq.enqueue(val)
print(cq.dequeue()) # 10
print(cq.dequeue()) # 20
cq.enqueue(60) # Wraps to position 0
cq.enqueue(70) # Goes to position 1Returns the front element without removing it or changing any pointers.
def peek(self):
if self.is_empty():
print("Queue is empty")
return None
return self.queue[self.front]
cq = CircularQueue(5)
for val in [10, 20, 30]:
cq.enqueue(val)
print(cq.peek()) # 10
print(cq.peek()) # 10 (still there, peek does not remove)
print(cq.dequeue()) # 10 (now actually removed)
print(cq.peek()) # 20 (new front)Returns the most recently enqueued element without removing it.
def get_rear(self):
if self.is_empty():
print("Queue is empty")
return None
return self.queue[self.rear]def is_empty(self): return self.front == -1isFull (Two Approaches)
# Approach 1: Use a separate size counter (recommended, simpler)
def is_full(self): return self.size == self.capacity
# Approach 2: Pointer arithmetic only (no extra variable)
def is_full_pointers_only(self):
return (self.front == 0 and self.rear == self.capacity - 1) or \
(self.front == self.rear + 1)class CircularQueue:
def __init__(self, capacity=100):
self.queue = [None] * capacity
self.capacity = capacity
self.front = -1
self.rear = -1
self.size = 0
def is_empty(self): return self.front == -1
def is_full(self): return self.size == self.capacity
def get_size(self): return self.size
def enqueue(self, element):
if self.is_full():
print("Queue Overflow"); return False
if self.is_empty():
self.front = 0; self.rear = 0
else:
self.rear = (self.rear + 1) % self.capacity
self.queue[self.rear] = element
self.size += 1
return True
def dequeue(self):
if self.is_empty():
print("Queue Underflow"); return None
value = self.queue[self.front]
if self.front == self.rear:
self.front = -1; self.rear = -1
else:
self.front = (self.front + 1) % self.capacity
self.size -= 1
return value
def peek(self): return None if self.is_empty() else self.queue[self.front]
def get_rear(self): return None if self.is_empty() else self.queue[self.rear]
def display(self):
if self.is_empty():
print("[ Empty Queue ]"); return
print("Queue: [ ", end="")
i = self.front
for _ in range(self.size):
print(self.queue[i], end=" ")
i = (i + 1) % self.capacity
print(f"] FRONT={self.front} REAR={self.rear} SIZE={self.size}")
# Full demo
cq = CircularQueue(5)
for val in [1, 2, 3, 4, 5]:
cq.enqueue(val)
print(f"Is full:{cq.is_full()}") # True
cq.display() # Queue: [ 1 2 3 4 5 ] FRONT=0 REAR=4
cq.enqueue(6) # Queue Overflow
print(f"Dequeued:{cq.dequeue()}") # 1
print(f"Dequeued:{cq.dequeue()}") # 2
cq.display() # Queue: [ 3 4 5 ] FRONT=2 REAR=4
cq.enqueue(6) # Wraps to index 0
cq.enqueue(7) # Goes to index 1
cq.display() # Queue: [ 3 4 5 6 7 ] FRONT=2 REAR=1
print(f"Peek:{cq.peek()}") # 3
print(f"Rear:{cq.get_rear()}") # 7A linked-list-based circular queue avoids the fixed-size limitation. The last node’s nextalways points back to the first node.
class Node:
def __init__(self, data):
self.data = data
self.next = None
class CircularQueueLinkedList:
def __init__(self):
self.front = None
self.rear = None
self.size = 0
def is_empty(self): return self.front is None
def enqueue(self, data):
new_node = Node(data)
if self.is_empty():
self.front = new_node
self.rear = new_node
new_node.next = self.front # Points to itself: circular
else:
new_node.next = self.front # New node → front
self.rear.next = new_node # Old rear → new node
self.rear = new_node # Update rear
self.size += 1
def dequeue(self):
if self.is_empty():
print("Queue is empty"); return None
value = self.front.data
if self.front == self.rear: # Only one node
self.front = None
self.rear = None
else:
self.front = self.front.next
self.rear.next = self.front # Maintain circular link
self.size -= 1
return value
def peek(self):
return None if self.is_empty() else self.front.data
def display(self):
if self.is_empty(): print("Empty"); return
current = self.front
print("Queue: ", end="")
while True:
print(current.data, end=" -> ")
current = current.next
if current == self.front: break
print("(back to front)")
cq_ll = CircularQueueLinkedList()
cq_ll.enqueue(14); cq_ll.enqueue(22); cq_ll.enqueue(6); cq_ll.enqueue(20)
cq_ll.display() # Queue: 14 -> 22 -> 6 -> 20 -> (back to front)
print(cq_ll.dequeue()) # 14
print(cq_ll.dequeue()) # 22
cq_ll.display() # Queue: 6 -> 20 -> (back to front)
cq_ll.enqueue(9)
print(f"Rear:{cq_ll.rear.data}") # 9
print(f"Front:{cq_ll.front.data}") # 6C (Linked List Implementation):
#include<stdio.h>
#include<stdlib.h>
struct Node {
int data;
struct Node* link;
};
struct Node* front = NULL;
struct Node* rear = NULL;
bool is_empty_ll() { return front == NULL; }
void enqueue_ll(int value) {
struct Node* newNode = (struct Node*) malloc(sizeof(struct Node));
newNode->data = value;
newNode->link = NULL;
if (is_empty_ll()) {
front = newNode;
} else {
rear->link = newNode;
}
rear = newNode;
rear->link = front; // Maintain circular link: rear always points to front
}
int dequeue_ll() {
if (is_empty_ll()) { printf("Queue is empty\n"); return -1; }
int value;
struct Node* temp = front;
value = temp->data;
if (front == rear) {
front = rear = NULL;
} else {
front = front->link;
rear->link = front; // Keep circular
}
free(temp);
return value;
}
void display_ll() {
if (is_empty_ll()) { printf("Queue is empty\n"); return; }
struct Node* temp = front;
printf("Queue: ");
do {
printf("%d -> ", temp->data);
temp = temp->link;
} while (temp != front);
printf("(front)\n");
}
int main() {
enqueue_ll(14); enqueue_ll(22); enqueue_ll(6);
printf("Initial: "); display_ll();
printf("Deleted:%d\n", dequeue_ll());
printf("After: "); display_ll();
return 0;
}Operation | Time Complexity | Explanation |
|---|---|---|
| O(1) | One modulo calculation + one array assignment |
| O(1) | One array read + one modulo calculation |
| O(1) | Direct index access at FRONT |
| O(1) | Direct index access at REAR |
| O(1) | Single comparison |
| O(1) | Single comparison (with size counter) |
| O(n) | Must visit all n elements |
Implementation | Space Complexity | Notes |
|---|---|---|
Array-based | O(n) | Fixed-size array of capacity n |
Linked list-based | O(n) | Dynamic nodes, each with data + next pointer |
The O(1) Guarantee: Every primary operation on a circular queue runs in O(1) time. This guaranteed constant-time performance is critical for real-time systems where each enqueue or dequeue must complete in a predictable, bounded amount of time regardless of how many elements are in the queue.
Feature | Linear Queue | Circular Queue | Deque |
|---|---|---|---|
Memory reuse of freed positions | No | Yes | Yes |
“False full” overflow | Yes (classic problem) | No | No |
Insertion | Rear only | Rear only | Both ends |
Deletion | Front only | Front only | Both ends |
Fixed-size efficiency | Poor | Excellent | Excellent |
Implementation complexity | Simple | Moderate (modulo logic) | Moderate |
Natural for cyclic processes | No | Yes | No |
Best for | Simple one-time queues | Streaming buffers, schedulers | Flexible both-ends access |
Feature | Python | JavaScript | Java | C |
|---|---|---|---|---|
Built-in circular queue |
| No native | No bounded built-in | No built-in |
Manual enqueue |
|
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Manual dequeue |
|
|
|
|
isFull |
|
|
|
|
isEmpty |
|
|
|
|
Auto-drop oldest when full |
| Manual | Manual | Manual |
Key formula |
|
|
|
|
collections.deque(maxlen=n) as a Circular Bufferfrom collections import deque
# maxlen creates a bounded deque that automatically drops oldest items when full
circular_buffer = deque(maxlen=5)
for i in range(1, 6):
circular_buffer.append(i)
print(circular_buffer) # deque([1, 2, 3, 4, 5])
circular_buffer.append(6) # 1 is automatically dropped!
print(circular_buffer) # deque([2, 3, 4, 5, 6])
circular_buffer.append(7) # 2 is automatically dropped!
print(circular_buffer) # deque([3, 4, 5, 6, 7])
# Dequeue from front
print(circular_buffer.popleft()) # 3
print(circular_buffer[0]) # 4 (peek front)
print(circular_buffer[-1]) # 7 (peek rear)Circular queues power systems that continuously process data streams within a fixed memory budget.
When you stream a video, audio/video packets arrive from the network and are stored in a circular buffer. The decoder reads from the front while new data arrives at the rear. The buffer circulates continuously without ever running out.
class AudioBuffer:
def __init__(self, buffer_size):
self.buffer = CircularQueue(buffer_size)
def receive_packet(self, packet_id):
"""Network thread adds incoming audio packets."""
if self.buffer.is_full():
print(f"Buffer full: dropping oldest packet")
self.buffer.dequeue() # Drop oldest for new data
self.buffer.enqueue(packet_id)
print(f"Buffered:{packet_id}")
def play_next(self):
"""Audio output thread reads at a steady rate."""
if self.buffer.is_empty():
print("Buffer empty: audio stutter!")
return None
packet = self.buffer.dequeue()
print(f"Playing:{packet}")
return packet
audio = AudioBuffer(buffer_size=5)
for i in range(1, 6):
audio.receive_packet(f"audio_{i}")
audio.play_next() # Playing: audio_1
audio.play_next() # Playing: audio_2
audio.receive_packet("audio_6") # Fits now: space freed by playbackIn round-robin CPU scheduling, each process gets an equal time slice. After the last process runs, the scheduler returns to the first process.
class RoundRobinScheduler:
def __init__(self, time_slice):
self.ready_queue = CircularQueue(20)
self.time_slice = time_slice
def add_process(self, name, burst_time):
self.ready_queue.enqueue({"name": name, "remaining": burst_time})
print(f"Process{name} added")
def run_one_cycle(self):
if self.ready_queue.is_empty():
print("No processes"); return
process = self.ready_queue.dequeue()
process["remaining"] -= self.time_slice
remaining = max(0, process["remaining"])
print(f"Running:{process['name']} | Remaining:{remaining}ms")
if process["remaining"] > 0:
self.ready_queue.enqueue(process) # Re-add to rear if not done
else:
print(f"Process{process['name']} COMPLETED")
scheduler = RoundRobinScheduler(time_slice=10)
scheduler.add_process("Chrome", 35)
scheduler.add_process("Spotify", 20)
scheduler.add_process("VSCode", 15)
for _ in range(7):
scheduler.run_one_cycle()
# Chrome(25ms), Spotify(10ms), VSCode(5ms), Chrome(15ms), Spotify DONE, VSCode DONE, Chrome(5ms)Solves the linear queue memory waste problem: The defining advantage. A circular queue reuses every dequeued position for future insertions. The same 5-position array can serve unlimited enqueue/dequeue cycles without ever falsely reporting “full.” This makes circular queues ideal for continuous data streams in fixed memory
O(1) guaranteed for all primary operations: Every enqueue, dequeue, peek, and isEmpty check executes in constant time with no exceptions. This predictable constant-time performance is critical for real-time systems where timing guarantees are required
Maximum utilisation of allocated memory: The capacity is set once and used continuously and completely. Unlike a linear queue that exhausts its array from one direction, a circular queue keeps 100% of its allocated capacity usable as long as it does not exceed capacity simultaneously held elements
Simpler than dynamic resizing: Alternatives to the linear queue overflow problem include resizing (O(n) copy), shifting (O(n) work), or growing the array. Circular queues solve the same problem in O(1) using only the modulo formula
Natural model for cyclic processes: Round-robin scheduling, audio buffers, traffic signal control, and ring topology networks are all inherently cyclic. A circular queue models these processes directly without any adaptation
Fixed size limitation: The capacity must be set at creation and cannot change. If demand exceeds fixed capacity, elements must be dropped or the structure replaced with a dynamic alternative
Complex isFull condition: Determining fullness requires checking two separate conditions without a size counter. Using only REAR == SIZE - 1 is a common bug that misses the wrap-around full case
More complex implementation than linear queue: The modulo arithmetic, two-case full condition, and special empty-to-non-empty transitions make circular queues more complex to implement and debug correctly
No random access: Only the front element is directly accessible. Accessing any other element requires dequeuing all elements ahead of it, destroying them in the process
Debugging difficulty: When REAR < FRONT (after wrap-around), the logical element order does not match the physical array layout. Printing the raw array does not show elements in queue order, making print-based debugging confusing
The circular queue solves one of the most fundamental inefficiencies in data structures with a single elegant idea and a single formula. Here is a recap of everything covered:
A circular queue connects the last array position back to the first using modulo arithmetic: (index + 1) % SIZE. This wrap-around formula is the entire mechanism that separates a circular queue from a linear one
The space waste problem of linear queues occurs when REAR reaches SIZE-1 and the queue reports full even though dequeued positions at the front are empty. Circular queues solve this by wrapping REAR back to index 0, reusing those freed positions
Two pointers, FRONT and REAR, track the oldest and newest elements. Both move forward with (pointer + 1) % SIZE and wrap to 0 when they exceed the last index
The isFull condition has two cases: linear-full (FRONT == 0 AND REAR == SIZE-1) and wrap-full ((REAR+1) % SIZE == FRONT). Using a separate size counter simplifies this to size == capacity
All six core operations: enqueue, dequeue, peek, rear, isEmpty, isFull run in O(1) time. This guaranteed constant performance is why circular queues are used in real-time systems
Circular queues are implemented either with a fixed-size array (simpler, cache-friendly) or a linked list (dynamic size, pointer overhead per node)
Key real-world applications include audio/video streaming buffers, CPU round-robin schedulers, traffic signal controllers, keyboard input buffers, and network packet buffers in routers
The most common implementation mistakes are: using only REAR == SIZE - 1 as the full check (misses the wrap-around full case), and not resetting both FRONT and REAR to -1 when the last element is dequeued
The circular queue teaches a fundamental principle of data structure design: often the most powerful improvements come not from building something entirely new, but from adding one connection to an existing structure.
The linear queue already had everything needed: two pointers, a fixed array, FIFO ordering. The circular queue adds one thing: the connection from the last position back to the first, captured entirely in the formula (index + 1) % SIZE.
That one change solves the memory waste problem completely and enables continuous, efficient operation on fixed memory resources.
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